How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Simplify \(\frac{3}{2x - 1}\) + \(\frac{2 - x}{x - 2}\)
\(\frac{2 - x}{(2x - 1)(x - 2)}\)
\(\frac{5 - x}{(2x - 1)(x - 2)}\)
\(\frac{4 - 2x}{2x - 1}\)
\(\frac{6 - 3x}{(2x - 1)(x - 2)}\)
Correct answer is C
\(\frac{3}{2x - 1}\) + \(\frac{2 - x}{x - 2}\)
= \(\frac{3}{2x - 1}\) - \(\frac{x - 2}{x - 2}\)
= \(\frac{3}{2x - 1}\) - 1
= \(\frac{3 - (2x - 1)}{2x - 1}\)
= \(\frac{3 - 2x + 1}{2x - 1}\)
= \(\frac{4 - 2x}{2x - 1}\)
In a regular polygon of n sides, each interior angle is 144°. Find n
12
11
10
8
6F
Correct answer is C
Formula for an interior angle of a polygon is (2n - 4) x 90
(2n - 4) x 90 = 144n
190n - 360 = 144n
n = \(\frac{360}{36}\)
= 10
0.05cm
0.5cm
0.045cm
0.005cm
0.004cm
Correct answer is D
Maximum error in measurement to 2 decimal places
Maximum error = \(\frac{1}{2}\) x 0.001
= 0.005
150o
67\(\frac{1}{2}\)o
67o
135o
68o
Correct answer is B
Representing from Asia is 150
\(\frac{150}{800}\) x 360
= \(\frac{135}{2}\)
= 67\(\frac{1}{2}\)°
If \(\frac{3e + f}{3f - e}\) = \(\frac{2}{5}\), find the value of \(\frac{e + 3f}{f - 3e}\)
\(\frac{5}{2}\)
1
\(\frac{26}{7}\)
\(\frac{1}{3}\)
Correct answer is C
\(\frac{3e + f}{3f - e}\) = \(\frac{2}{5}\)
= 3e + f
= 2 x 1
\(\frac{-e + 3f}{3e - f}\) = \(\frac{5 \times 3}{2}\)
= \(\frac{3e + 9f = 15}{10f = 17}\)
f = \(\frac{17}{10}\)
Sub. for equ. (1)
3e + \(\frac{17}{10}\) = 2
3e = 2 - \(\frac{17}{10}\)
\(\frac{3}{10}\)
e = \(\frac{3}{10}\) x \(\frac{1}{3}\)
= \(\frac{1}{10}\)
= e + 3f = \(\frac{1}{10}\) + \(\frac{3 \times}{10}\) = \(\frac{52}{10}\)
f - 3e = \(\frac{17}{10}\) - 3 x \(\frac{1}{10}\)
= \(\frac{14}{10}\)
= \(\frac{52}{10}\) x \(\frac{10}{14}\)
= \(\frac{26}{7}\)