2−x(2x−1)(x−2)
5−x(2x−1)(x−2)
4−2x2x−1
6−3x(2x−1)(x−2)
Correct answer is C
32x−1 + 2−xx−2 = 32x−1 - x−2x−2 = 32x−1 - 1 = 3−(2x−1)2x−1 = 3−2x+12x−1 = 4−2x2x−1
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