How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
If 4\(^{3x}\) = 16\(^{x+1}\), find the value of x
2
3
4
5
Correct answer is A
4\(^{3x}\) = 4\(^{2(x+1)}\)
3x = 2x + 2
3x - 2x = 2
x = 2
2
3
5
6
Correct answer is B
23 x 54 = 1242
In mod 7;
1242 ÷ 7 = 177 R 3
Hence; 1242 ≡ 3
If √24 + √96 - √600 = y√6, find the value of y
4
2
-2
-4
Correct answer is D
√24 + √96 - √600 = y√6
convert all to basic surds
√24 = 2√6
√96 = 4√6
- √600 = -10√6
2√6 + 4√6 - 10√6 = -4√6
value of y = -4
Given that A and B are sets such that n(A) = 8, n(B)=12 and n(AnB) =3, find n(AuB).
15
17
20
23
Correct answer is B
n(AuB) = n(A) + n(B) - n(AnB)
n(AuB) = 8 + 12 - 3
= 17
Change 432\(_{five}\) to a number in base three.
10100\(_{three}\)
11100\(_{three}\)
11101\(_{three}\)
10110\(_{three}\)
Correct answer is B
Convert from base 5 to base 10
432\(_{five}\) = (4 x 5\(^2\)) + (3 x 5\(^1\)) + (2 x 5\(^0\))
= (4 x 25) + (3 x 5) + (2 x 1)
= 100 + 15 + 2
= 117\(_{ten}\)
Then convert from base 10 to base 3
| 3 | 117 |
| 3 | 39 r 0 |
| 3 | 13 r 0 |
| 3 | 4 r 1 |
| 3 | 1 r 1 |
| 0 r 1 |
Selecting the remainders from bottom to top:
117\(_{ten}\) = 11100\(_{three}\)
Hence; 432\(_{five}\) = 11100\(_{three}\)