If 4\(^{3x}\) = 16\(^{x+1}\), find the value of x 

A.

2

B.

3

C.

4

D.

5

View answer & explanation

Correct answer is A

4\(^{3x}\) = 4\(^{2(x+1)}\)

3x = 2x + 2

3x - 2x = 2

x = 2

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