How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
If p = [\(\frac{Q(R - T)}{15}\)]\(^ \frac{1}{3}\), make T the subject of the relation
T = R + \(\frac{P^3}{15Q}\)
T = R - \(\frac{15P^3}{Q}\)
T = R + \(\frac{P^3}{15Q}\)
T = 15R - \(\frac{Q}{P^3}\)
Correct answer is B
Cubic both sides; P3 = \(\frac{Q(R - T)}{15}\)
(cross multiplication) Q(R - T) = 15P3
(divide both sides by Q); R - T = 15\(\frac{1}{Q}\)
(subtract r from both sides) - T = \(\frac{15P^3}{Q - R}\)
T = R - \(\frac{15P^3}{Q}\)
22cm2
44cm3
77cm3
3082
Correct answer is C
Volume = \(\frac{1}{3} \pi r^2h = \frac{1}{3} \times \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times \frac{6}{1}\)
V = \(\frac{6468}{84}\)
= 77cm3
If loga270 - loga10 + loga \(\frac{1}{3}\) = 2, what is the value of a?
3
4
5
6
Correct answer is A
loga270 - loga10 + loga\(\frac{1}{3}\) = 2
loga270 + loga\(\frac{1}{3}\) - loga10 = 2
loga(270\(\frac{\frac{1}{3}}{10}\)) = 2
loga9 = 2
aa = 9
a = \(\sqrt{9}\) = 3
Which of these equations best describes the points of intersection of the curve and the line?
\(x^2 + 5x - 6 = 0\)
x2 - 5x - 6 = 0
x2 + x - 6 = 0
x2 - x - 6 = 0
Correct answer is C
The roots are -3 and 1
x = -3 and x = 1
y = (x + 3)(x - 1)
= x2 - x + 3x - 3
y = x2 + x - 6 = 0
If x + y = 12 and 3x - y = 20, find the value of 2x - y
8
10
12
15
Correct answer is C
x + y = 12 + 3x - y = 20 --------------- 4x = 32 x = 8 x + y = 12; 8 + y = 12; y = 12 - 8 = 4 2x - y = 2(8) - 4; 16 - 4 = 12