If log_a270 - log_a10 + log_a \(\frac{1}{3}\) = 2, what is the value of a?

A.

3

B.

4

C.

5

D.

6

View answer & explanation

Correct answer is A

log_a270 - log_a10 + log_a\(\frac{1}{3}\) = 2

log_a270 + log_a\(\frac{1}{3}\) - log_a10 = 2

log_a(270\(\frac{\frac{1}{3}}{10}\)) = 2

log_a9 = 2

a^a = 9

a = \(\sqrt{9}\) = 3

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