How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Using the diagram, find the bearing of X from Y
300o
240o
120o
60o
Correct answer is B
The bearing of X from Y
= 360 - 120 = 240
In the diagram, \SQ\ = 4cm, \PT\ = 7cm. /TR/ = 5cm and ST//OR. If /SP/ = xcm, find the value of x
5.6
6.5
6.6
6.8
Correct answer is A
\(\frac{/PS/}{/PQ/} = \frac{/PT/}{/PR/}\)
\(\frac{x}{4 + x} = \frac{7}{7 + 5}\)
\(\frac{x}{4 + x} = \frac{7}{12}\)
(2x = 7)(4 + x); 12x = 28 + 7x
12x - 7x = 28
5x = 28
x = \(\frac{28}{5}\)
x = 5.6
Find the value of x in the diagram
50o
30o
22o
17o
Correct answer is D
Sum of exterior angles of a polygon = 360o
(x + 64) + 2x + (3x - 54) + 5x + 4x + 3x + (2x + 10) = 360o
20x + 20 = 360o
20x + 360 - 20 = 340o
x = \(\frac{340}{20}\)
x = 17o
In the diagram, IG is parallel to JE, JEF = 120o and FHG = 130o, fins the angle marked t
40o
70o
80o
100o
Correct answer is B
Now, t + 60o + 50o = 180o
t = 180o - 110o
t = 70o
In the diagram, /TP/ = 12cm and it is 6cm from O, the centre of the circle, Calculate < TOP
120o
90o
60o
45o
Correct answer is B
Tan \(\theta = \frac{6}{6} = 1\)
\(\theta\) = tab - 1(1) = 45o
< top = 20
= 2 x 45o = 90o