In the diagram, \SQ\ = 4cm, \PT\ = 7cm. /TR/ = 5cm and ST...
In the diagram, \SQ\ = 4cm, \PT\ = 7cm. /TR/ = 5cm and ST//OR. If /SP/ = xcm, find the value of x
5.6
6.5
6.6
6.8
Correct answer is A
/PS//PQ/=/PT//PR/
x4+x=77+5
x4+x=712
(2x = 7)(4 + x); 12x = 28 + 7x
12x - 7x = 28
5x = 28
x = 285
x = 5.6