In the diagram, IG is parallel to JE, JEF = 120o and FHG = 130o, fins the angle marked t

In the diagram, IG is parallel to JE, JEF = 120^o and FHG = 130^o, fins the angle marked t

A.

40^o

B.

70^o

C.

80^o

D.

100^o

View answer & explanation

Correct answer is B

Now, t + 60^o + 50^o = 180^o

t = 180^o - 110^o

t = 70^o

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