Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

1,331.

The shaded portion in the diagram is the solution of

A.

x + y \(\leq\) 3

B.

x + y < 3

C.

x + y > 3

D.

x + y \(\geq\) 3

Correct answer is B

Using \(\frac{x}{a} + \frac{y}{b}\) < 1for the equation of the time

where a = intercept on x-axis and b = intercept on y - axis

\(\frac{x}{3} + \frac{y}{3} = 1\)

= \(\frac{x + y}{3} = 1\)

= x + y < 3

1,332.

In the diagram, O is the centre of the circle, < SQR = 60o, < SPR = y and < SOR = 3x. Find the value of (x + y)

A.

110o

B.

100o

C.

80o

D.

70o

Correct answer is B

3x = 2 x 60 = 2y (Angle at centre = 2 x angle at circumference)

3x = 2 x 60

x = \(\frac{2 \times 60}{3}\) = 40o

2 x 60 = 2y

y = 60o

x + y = 40 + 60

= 100o

1,333.

In the diagram, the tangent MN makes an angle of 55o with the chord PS. IF O is the centre of the circle, find < RPS

A.

55o

B.

45o

C.

35o

D.

25o

Correct answer is C

Join SR

< PRS = 90o(Angle in a semicircle)

< PRS = 55o (Angle between a chord and a tangent = Angle in the alternate segment)

< PSR + < PRS + < RSP = 180o

90v + 55o + < RSp = 180o

< RSP = 180o - 145o

= 35o

1,334.

In the diagram, < ROS = 66o and < POQ = 3x. some construction lines are shown. Calculate the value of x.

A.

10o

B.

11o

C.

22o

D.

35o

Correct answer is B

From the diagram, OP bisects < ROS

< POS = \(\frac{1}{2}\) < ROS = \(\frac{1}{2}\) x 66o

3x = 33o

x = \(\frac{33^o}{3}\)

= 11o

1,335.

In the diagram, triangles HKL and HIJ are similar. Which of the following ratios is equal to \(\frac{LH}{JH}\)

A.

\(\frac{KL}{JI}\)

B.

\(\frac{HK}{JK}\)

C.

\(\frac{JI}{KL}\)

D.

\(\frac{HK}{LK}\)

Correct answer is A

\(\bigtriangleup\) is similar to \(\bigtriangleup\) HIJ

< HKL = HJI = xo

Hence, \(\frac{LH}{JH} = \frac{KH}{JH} \frac{KL}{IJ}\)

\(\frac{LH}{JH} = \frac{KL}{JI}\)