\(\frac{KL}{JI}\)
\(\frac{HK}{JK}\)
\(\frac{JI}{KL}\)
\(\frac{HK}{LK}\)
Correct answer is A
\(\bigtriangleup\) is similar to \(\bigtriangleup\) HIJ
< HKL = HJI = xo
Hence, \(\frac{LH}{JH} = \frac{KH}{JH} \frac{KL}{IJ}\)
\(\frac{LH}{JH} = \frac{KL}{JI}\)