How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
In the diagram, < WOX = 60o, < YOE = 50o and < OXY = 30o. What is the bearing of x from y?
300o
240o
190o
150o
Correct answer is A
The bearing of x from y = 270o + \(\theta\)
where \(\theta\) + 50o = y
in \(\bigtriangleup\) OXY
O + X + Y = 180o
Where O = 40o + 30o = 70o
70o + 30o + y = 180o
y + 100o = 180o
y = 180o - 100o = 30o
\(\theta\) + 50o = 80o
80o - 50o = 30o
The bearing of x from y = 270o + 30o = 300o
In the diagram, 0 is the centre of the circle. Find the value x
34
29
17
14
Correct answer is D
POQ in a straight line
Hence, < POQ + < QOR = 180o
56o + < QOR = 180o
< QOR = 180o - 56o
= 124o
Now, in \(\bigtriangleup\) QOR OR = OQ = Radius
< ORQ = < OQR = 2x (Base angles of an Isosceles \(\bigtriangleup\))
2x + 124 + 2x = 180o
4x + 124 = 180
4x = 180 - 124
4x = 56
x = \(\frac{56}{4}\)
x = 14o
44cm2
99cm2
154cm2
165cm2
Correct answer is B
Area of remaining = Area of rectangle = Area of semi-circle
22 x 8 - \(\frac{1}{2}\)xar2
ehere r - \(\frac{14}{2}\)cm = 7cm
Area of remaining = 176 - \(\frac{1}{2}\) x \(\frac{22}{4}\) x 7 x 7
= 176 - 77
= 99cm2
The diagram is a net right rectangular pyramid. Calculate the total surface area
208cm2
112cm2
92cm2
76cm2
Correct answer is C
Total surface area = sum of the area of the \(\bigtriangleup\) S + Area of the rectangle
= 2 x Area of \(\bigtriangleup\) PTQ + 2 x Area of \(\bigtriangleup\) QUR + Area of rectangle PQRS
2 x \(\frac{1}{2}\)(8 x 4) + 2 x \(\frac{1}{2}\)(5 x 4) + 8 x 5
= 32 + 20 + 40
= 92cm2
In the diagram, GI is a tangent to the circle at H. If EF//GI, calculate the size of < EHF
126o
72o
64cmo
32cmo
Correct answer is B
F = 54o (Alternate triangle angles)
< GHE = F = 54o(Angle between a chord and a tangent = angles in the alternate segment)
Now, < GHE + < EHF + < IHF = 180o(Angles on a straight line)
54o + < EHF + 54o = 180o
< EHF = 180o - 108o
= 72o