How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Find the value of x if \( [ 1 ÷ 64^{(x + 2)}]= [4^{(x − 3)} ÷ 16^x ] \)
\( \frac{3}{2} \)
\( \frac{2}{3} \)
\( \frac{1}{3} \)
\( -\frac{3}{2} \)
Correct answer is D
\( [ 1 ÷ 64^{(x + 2)}]= [4^{(x − 3)} ÷ 16^x ] \)
\( 64^{−(x + 2)} = [4^{(x − 3)}] ÷[16^x] \)
breakdown 4,16,64 into a small index no
\( 2^{−6(x + 2)} = 2^{2(x − 3)} ÷ 2^{4(x)} \)
\( 2^{−6x− 12} = 2^{2x − 4x − 6} \)
\( 2^{−6x −12} = 2^{−2x − 6} \)
− 6x − 12 = − 2x − 6
Collect the like term
−6x + 2x = −6 + 12
−4x =6
x = \( \frac{6}{4} \)
x = \( \frac{−3}{2} \)
A man sells his new brand car for N420,000 at a gain of 15%. What did it cost him?
N410,000
N365, 217
N157, 250
N257,000
Correct answer is B
Cost Price:
Selling price = 100 : (100 + 15)
= 100 : 115
Cost Price
= 100 ÷ 115 of selling price (i.e N420,000)
= 100 ÷ 115 × N420,000
= N365,217.4
∴ Cost Price = N365, 217
5
3
6
1
Correct answer is C
132x = 708
\( 1 × x^2 + 3 × x^1 + 2 × x^0 \)
\( 7 × 8^1 + 0 × 8^0 \)
\( x^2 + 3x + 2 − 56 = 0 \)
\( x^2 + 3x − 54 = 0 \)
x(x + 9)−6(x + 9) = 0
(x + 9)(x − 6) = 0
Either (x + 9) = 0 or (x − 6) = 0
x = − 9 or +6
The positive values for x = 6
The base number for 132x = 1326
Given that A = {3, 4, 1, 10, ⅓ }
B = {4, 3,⅓, ⅓, 7}.
Find A∩B
{}
{⅓, 1, 2}
{3, 4, ⅓}
{1, 3, ⅓}
Correct answer is C
A ∩ B = {3, 4, ⅓}
\( \frac{2}{15} \)
\( \frac{3}{24} \)
\( \frac{3}{21} \)
\( \frac{3}{28} \)
Correct answer is B
No explanation has been provided for this answer.