32
23
13
−32
Correct answer is D
[1÷64(x+2)]=[4(x−3)÷16x]
64−(x+2)=[4(x−3)]÷[16x]
breakdown 4,16,64 into a small index no
2−6(x+2)=22(x−3)÷24(x)
2−6x−12=22x−4x−6
2−6x−12=2−2x−6
− 6x − 12 = − 2x − 6
Collect the like term
−6x + 2x = −6 + 12
−4x =6
x = 64
x = −32
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