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Find the value of x if \( [ 1 ÷ 64^{(x + 2)}]= [4^{(x − 3...

Find the value of x if [1÷64(x+2)]=[4(x3)÷16x]

A.

32

B.

23

C.

13

D.

32

Correct answer is D

[1÷64(x+2)]=[4(x3)÷16x]

64(x+2)=[4(x3)]÷[16x]

breakdown 4,16,64 into a small index no

26(x+2)=22(x3)÷24(x)

26x12=22x4x6

26x12=22x6

− 6x − 12 = − 2x − 6

Collect the like term

−6x + 2x = −6 + 12

−4x =6

x = 64

x = 32