Learn more about the properties, composition, and structure of substances (elements and compounds) with these Chemistry questions and answers. This Test can be used by students preparing for Chemistry in JAMB, WAEC, NECO or Post UTME.
Which of the following produces relatively few ions in solution?
NaOH
Ca(OH)\(_2\)
KOH
AI(OH)\(_3\)
Correct answer is D
Aluminium hydroxide is not soluble in water because it is polymeric and it also has high lattice energy and therefore it is hard to break bonds in this compound. So, water cannot dissolve such types of compounds.
Al(OH)\(_3\) is not soluble in water
The choice of method for extracting a metal from its ores depends on the
strength of the core
position of the metal in the electrochemical series
source of the core
position of the metal in the periodic table
Correct answer is B
The method used to extract a metal from its ore depends upon the stability of its compound in the ore, which in turn depends upon the reactivity of the metal:
• The oxides of very reactive metals, such as aluminum, form stable oxides and other compounds. A lot of energy is needed to reduce them to extract the metal.
• The oxides of lesser reactive metals, such as iron, form less stable oxides and other compounds. Relatively little energy is needed to reduce them to extract the metal.
So, the method of extraction of a metal from its ore depends on the metal's position in the reactivity series.
Calculate the pH of 0.05 moldm\(^{-3}\) H\(_2\)SO\(_4\)
1.30
1.12
1.00
0.30
Correct answer is C
Recall from pH formula pH = -Log [H+]
H2SO4 → 2H+ + SO42-
2H+ → 2 X0.05 = 0.1
pH= -Log [0.1] = 1
7.64g
3.82g
1.91g
0.96g
Correct answer is C
M = \(\frac{MmIT}{96500n}\)
Where
M=mass
Mm = Molar mass = 64g/mol
I = current = 1.6A
T= Time =1h r=3600s
N= No of Charge = +2
M = \(\frac{64x \times 1.6 \times 3600}{96500 \times 2}\)
M=1.91g
The solubility of the solids that dissolves in a given solvent with the liberation of heat will
increase with an increase in temperature
decrease with an increase in temperature
decrease with a decrease in temperature
not be affected by changes in temperature
Correct answer is B
Increasing temperature in exothermic reaction favors the left/reactant side and decreasing temperature will favor the right/product side.