Chemistry questions and answers

Chemistry Questions and Answers

Learn more about the properties, composition, and structure of substances (elements and compounds) with these Chemistry questions and answers. This Test can be used by students preparing for Chemistry in JAMB, WAEC, NECO or Post UTME.

656.

Which of the following produces relatively few ions in solution?

A.

NaOH

B.

Ca(OH)\(_2\)

C.

KOH

D.

AI(OH)\(_3\)

Correct answer is D

Aluminium hydroxide is not soluble in water because it is polymeric and it also has high lattice energy and therefore it is hard to break bonds in this compound. So, water cannot dissolve such types of compounds.

Al(OH)\(_3\) is not soluble in water

657.

The choice of method for extracting a metal from its ores depends on the

A.

strength of the core

B.

position of the metal in the electrochemical series

C.

source of the core

D.

position of the metal in the periodic table

Correct answer is B

The method used to extract a metal from its ore depends upon the stability of its compound in the ore, which in turn depends upon the reactivity of the metal:

  • The oxides of very reactive metals, such as aluminum, form stable oxides and other compounds. A lot of energy is needed to reduce them to extract the metal.

  • The oxides of lesser reactive metals, such as iron, form less stable oxides and other compounds. Relatively little energy is needed to reduce them to extract the metal.

  So, the method of extraction of a metal from its ore depends on the metal's position in the reactivity series.

658.

Calculate the pH of 0.05 moldm\(^{-3}\) H\(_2\)SO\(_4\)

A.

1.30

B.

1.12

C.

1.00

D.

0.30

Correct answer is C

Recall from pH formula pH = -Log [H+]

  H2SO4 → 2H+ + SO42-

  2H+ → 2 X0.05 = 0.1

  pH= -Log [0.1] = 1

659.

What mass of Cu would be produced by the cathodic reduction of Cu\(^{2+}\)  when 1.60A of current passes through a solution of CuSO\(_4\) for 1 hour. (F=96500Cmol\(^{-1}\) , Cu=64)

A.

7.64g

B.

3.82g

C.

1.91g

D.

0.96g

Correct answer is C

M = \(\frac{MmIT}{96500n}\)

  Where

  M=mass

  Mm = Molar mass = 64g/mol

  I = current = 1.6A

  T= Time  =1h r=3600s

  N= No of Charge = +2

  M = \(\frac{64x \times 1.6 \times 3600}{96500 \times 2}\)

  M=1.91g

660.

The solubility of the solids that dissolves in a given solvent with the liberation of heat will

A.

increase with an increase in temperature

B.

decrease with an increase in temperature

C.

decrease with a decrease in temperature

D.

not be affected by changes in temperature

Correct answer is B

Increasing temperature in exothermic reaction favors the left/reactant side and decreasing temperature will favor the right/product side.