Learn more about the properties, composition, and structure of substances (elements and compounds) with these Chemistry questions and answers. This Test can be used by students preparing for Chemistry in JAMB, WAEC, NECO or Post UTME.
The constituent common to duralumin and alnico is
Co
Mn
Al
Mg
Correct answer is C
Constituents of duralumin are: Al, Cu, Mg, Mn.
Constituents of Alnico are: Al, Ni and Co
In 1909, the alloy of duralumin was discovered by Alfred Wilon consisting of 94% Al, 4% Cu, 1% Mg and 1% Mn(Manganese)
Alnico is an acronym referring to a family of iron alloys which in addition to iron are composed primarily of Al, Ni and Co.
The reaction between an organic acid and an alcohol in the presence of an acid catalyst is known as;
saponification
dehydration
esterification
hydrolysis
Correct answer is C
Esterification is a chemical reaction that forms at least one ester (= a type of compound produced by reaction between acids and alcohols). Esters are produced when acids are heated with alcohols in a process called esterification. An ester can be made by an esterification reaction of a carboxylic acid and an alcohol.
Diamond is a bad conductor of electricity because its bonding electrons are used in
crystal lattice formation
covalent bond formation
metallic bond formation
coordinate bond formation
Correct answer is B
Diamond is a covalent macromolecule, and typical of a covalent substance is an insulator. All valence electrons are localized in well-defined covalent bonds and hence are not free to move through the structure
450cm\(^3\)
300cm\(^3\)
200cm\(^3\)
150cm\(^3\)
Correct answer is A
From the dilution law
C\(_1\)V\(_1\) = C\(_2\)V\(_2\)
C\(_1\) = Initial Concentration of NaOH = 0.6M
V\(_1\) = Initial Volume of NaOH = 300cm3
C\(_2\) = Final Concentration of NaOH = 0.4M
V\(_2\) = Final Volume of NaOH = ?
V\(_2\) = \(\frac{C_1V_1}{C_2}\)
V\(_2\) = \(\frac{0.6 \times 300}{0.4}\)
V\(_2\) = 450 cm\(^3\)
Correct Computation as it follows the equation specified
5cm\(^3\)
10cm\(^3\)
20cm\(^3\)
50cm\(^3\)
Correct answer is D
2NaOH + H\(_2\) SO\(_4\)↔Na\(_2\)SO\(_4\) + 2H\(_2\)O
V x 0.5M = 2(10 x 1.25)
0.5V = 2 x 12.5
0.5V = 25
V = 250.5 = 50cm\(^2\)
Correct computation as it follows the equation specified.