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WAEC Mathematics Past Questions & Answers - Page 96

476.

The pie chart shows the distribution of 600 mathematics textbooks for Arts, Business, Science and Technical Classes. How many textbooks are for the technical class?

100

150

200

250

View answer & explanation

Correct answer is D

Arts = 90^o business = 75^o, science = 45^o

Technical 360^o - (90^o - 75^o + 45^o) = 360^o - 210^o

Technical = 150^o

textbooks for technical class = $\frac{150^o}{360^o}$ x 600

= 250

477.

Using the histogram, what is the median class?

60.5 - 70.5

50.5 - 60.5

40.5 - 50.5

30.5 - 40.5

View answer & explanation

Correct answer is C

No explanation has been provided for this answer.

478.

Using the histogram, estimate the mode of distribution

51.5

52.5

53.5

54.5

View answer & explanation

Correct answer is C

No explanation has been provided for this answer.

479.

In the diagram, O is the centre of the circle. OM||XZ and < ZOM = 25º. Calculate ∠XYZ

50^o

55^o

60^o

65^o

View answer & explanation

Correct answer is D

Angle in a semi-circle is 90º when OM is subtended

: (90 - 25)º

= 65º

480.

Find the value of m in the diagram

34^o

27^o

23^o

17^o

View answer & explanation

Correct answer is D

$\bigtriangleup$ ABC, A + 153 = 180 (angles on straight line)

< A = 180 - 153 = 27

< B = 2m(vertically opposite angles)

< C = 7m (corresponding ngles)

< A + < B + < C = 180 (sum of int. angles of $\bigtriangleup$ )

i.e. 27 + 2m + 7m = 180^o

9m = 180 - 27

9m = 153

m = $\frac{153}{9}$

= 17