Three quarters of a number added to two and a half of the number gives 13. Find the number
4
5
6
7
Correct answer is A
let the number be x
2\(\frac{1}{2}x + \frac{3}{4}x = 13\)
\(\frac{5}{2}x + \frac{3}{4}x = 13\)
multiply through by 4
4(\(\frac{5}{2}\))x + 4(\(\frac{3}{4}\))x = 13 x 4
2(5x) + 3x = 52
10x + 3x = 52
13x = 52
x = \(\frac{52}{13}\)
x = 4
Given that x > y and 3 < y, which of the following is/are true? i. y > 3 ii. x < 3 iii. x > y > 3
i
i and ii
i and iii
i, ii and iii
Correct answer is C
x > y and 3 < y; then 3 < y means that y > 3 x > 3 to give the possible x > y > 3
Simplify: \(\sqrt{12} ( \sqrt{48} - \sqrt{3}\))
18
16
14
12
Correct answer is A
\(\sqrt{12} ( \sqrt{48} - \sqrt{3}\))
\(\sqrt{4 \times 3} (6 \times 3 - \sqrt{3}) = 2 \sqrt{3}(4 \sqrt{3} - \sqrt{3})\)
= 2\(\sqrt{3} \times \sqrt{3} (4 - 1) 2\sqrt{9}(3) = 2 \times 3 \times 3 = 18\)
\(\frac{11}{18}\)
\(\frac{11}{20}\)
\(\frac{7}{22}\)
\(\frac{5}{19}\)
Correct answer is B
at most 2 marks = 5 + 2 + 4 students = 11 students
probability(at most 2 marks) = \(\frac{11}{20}\)
The volume of a cube is 512cm3. Find the length of its side
6cm
7cm
8cm
9cm
Correct answer is C
volume of cube = L x L x L
512cm3 = L3
L3 = 512cm3
L = 3\(\sqrt{512}\)
L (512)\(\frac{1}{3}\)
= (29)\(\frac{1}{3}\)
23 = 8cm
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