If log 5.957 = 0.7750, find log \(3 \sqrt{0.0005957}\)
4.1986
2.9250
1.5917
1.2853
Correct answer is B
\(3 \sqrt{0.0005957}\)
\(\begin{array}{c|c} \log No(0.0005957) & \frac{1}{3} \log \frac{1}{3} \\ \hline (0.0005957)^{\frac{1}{3}} & 4.7750 \times \frac{1}{3} \\ & 6 + 2.7750 \\\hline & 3 \\\hline & 2.9250\end{array}\)
\(\frac{5}{9}\)
1\(\frac{4}{9}\)
\(\frac{1}{3}\)
\(\frac{2}{9}\)
Correct answer is C
p = { 1, 2, 3}
Q = {2, 3, 5}
prob(prime number) = prob(1 and 2) or
= prob(2 and 3) or
= prob(3 and 2)
There are three possibilities of the sum being prime
Total possibility = 9
probability(sum being prime) = \(\frac{3}{9}\)
= \(\frac{1}{3}\)
15%
35%
65%
85%
Correct answer is C
No explanation has been provided for this answer.
\(\frac{1}{4}\)
\(\frac{1}{3}\)
\(\frac{2}{3}\)
\(\frac{3}{4}\)
Correct answer is C
There are 3 triangles: \(\bigtriangleup\)MRS, \(\bigtriangleup\) and \(\bigtriangleup\) PRQ
Area PRMS has 2 triangles: \(\bigtriangleup\) MRS and \(\bigtriangleup\) RSP
the fraction = \(\frac{2}{3}\)
14\(\frac{1}{3}\)cm
12\(\frac{5}{6}\)cm
8\(\frac{1}{7}\)cm
7\(\frac{1}{3}\)cm
Correct answer is A
perimeter of minor sector
2r + \(\frac{\theta}{360} \times 2 \pi r\)
= 2 x 3.5 + \(\frac{120^o}{360^o} \times 2 \frac{22}{7} \times 3.5\)
= 7 + \(\frac{154}{21}\)
= 7 + 7.33
= 14.33
= 14\(\frac{1}{3}\)cm