WAEC Mathematics Past Questions & Answers - Page 86

426.

Determine the value of m in the diagram

80^o

90^o

110^o

150^o

View answer & explanation

Correct answer is B

No explanation has been provided for this answer.

427.

In the figures, PQ is a tangent to the circle at R and UT is parallel to PQ. if < TRQ = x^o, find < URT in terms of x

2x^o

(90 - x)^o

(90 + x)^o

(180 - 2x)^o

View answer & explanation

Correct answer is D

< URT = < TRQ (angle alternate a tangent and a chord equal to angle in the alternate segment)

< RUT = x^o

In \(\bigtriangleup\) URT

< RUT + < RUT + < UTR = 180^o (sum of int. < s of \(\bigtriangleup\))

< URT + x + x = 180^o

< URT = 180^o - 2x

428.

The graph given is for the relation y = 2x² + x - 1. Find the minimum value of y

0.00

-0.65

-1.25

-2.10

View answer & explanation

Correct answer is C

No explanation has been provided for this answer.

429.

The graph given is for the relation y = 2x² + x - 1.What are the coordinates of the point S?

(1, 0.2)

(1, 0.4)

(1, 2.0)

(1, 40)

View answer & explanation

Correct answer is C

No explanation has been provided for this answer.

430.

In the diagram, ST is parallel to UW, < WVT = x^o, < VUT = y^o, < RSV = 45^o and < VTU = 20^o. Calculate the value of y

View answer & explanation

Correct answer is B

x^o + z^o = 180^o (sum of < on str. line)

45^o + z^o = 180^o

z^o = 180^o - 45^o

z = 135^o

z + y^o + 20^o = 180^o (sum of < s in \(\bigtriangleup\))

135^o + y^o + 20^o = 180^o

y^o + 155^o = 180^o

y^o + 180^o - 155^o

y^o = 25^o