Given that logx 64 = 3, evaluate x log28
6
9
12
24
Correct answer is C
If logx 64 = 3, then 64=x3
43=x3
Since the indices are equal,
x = 4
Hence, x log28
= 4(3.log22)
= where log22 = 1(1)
= 12 X 1
= 12
(x + 3)2
(x + 5)(x − 3)
(x − 5)2
(x − 5)(x + 3)
Correct answer is D
x2 − 2x − 15
(x2 − 5x) + (3x − 15)
x(x − 5)+ 3(x − 5)
(x − 5)(x + 3)
Given that A = {1, 5, 7} B = {3, 9, 12, 15} C = {2, 4, 6, 8} Find (A ∪ B) ∪ C
{1, 2, 3, 4, 5, 6, 7, 8, 9, 12, 15}
{1, 2, 3, 5, 6, 8, 12, 15}
{2, 4, 5, 9, 12, 15}
{1, 5, 6, 7, 8, 9, 12, 15}
Correct answer is A
{A ∪ B ∪ C}
{A ∪ B} = {1, 3, 5, 7, 9, 12, 15}
∪ C={2,4,6,8}
{A ∪ B} ∪ C = {1, 3, 5, 7, 9, 12, 15} ∪ {2, 4, 6, 8}
= {1, 2, 3, 4, 5, 6, 7, 8, 9, 12, 15}
{A ∪ B} ∪ C = {1, 2, 3, 4, 5, 6, 7, 8, 9, 12, 15}
Find at which rate per annum simple interest N525 will amount to N588 in 3 years.
3%
2%
5%
4%
Correct answer is D
I = A − P
= N588 − N525
∴I = N63
I = PRT ÷ 100
R = [100I ÷PT]
R = [(100 × 63 ) ÷ (525 × 3)]
= (6300 ÷ 1575) = 4
∴ The rate = 4 %
Make x the subject of the equation
s = 2 + t5(x + ⅗y)
x = 5[(s − 2) ÷ t] - 3/5y
x = 25[(s − 2) ÷ t] − 3ty
x = [1 ÷ (s − 2)3ty]
x = [5(s − 2) 2 ÷ 3ty] × t
Correct answer is A
No explanation has been provided for this answer.