HF,\(NH_3\), \(SiH_4\), \(CH_4\)
\(CH_4\), \(SiH_4\), HF, \(NH_3\),
\(NH_3\),\(CH_4\), \(SiH_4\), HF
\(CH_4\), \(SiH_4\), \(NH_3\), HF
Correct answer is A
The correct order of boiling points of the compounds \(NH_3\), HF, \(SiH_4\), and \(CH_4\) is HF, \(NH_3\), \(SiH_4\), \(CH_4\).
The correct order of boiling points of the compounds \(NH_3\), HF, \(SiH_4\), and \(CH_4\) is HF, \(NH_3\), \(SiH_4\), \(CH_4\).
The boiling point of a compound is the temperature at which the vapor pressure of the liquid is equal to the atmospheric pressure. The stronger the intermolecular forces, the higher the boiling point.
198 kJ of energy is given off
The reaction is exothermic
The reaction container would feel warm.
198 kJ of energy is absorbed
Correct answer is D
A positive value of ∆H (+198 kJ mol^-1) indicates that the reaction is endothermic, meaning it requires an input of energy to proceed. In this case, the reaction absorbs 198 kJ of energy per mole of reactants to convert 2 moles of \(SO_3\) into 2 moles of \(SO_2\) and 1 mole of \(O_2\). This means that the reaction container would need to be supplied with energy, and it would feel cooler rather than warmer.
The separation technique that is suitable for separating iodine from tetrachloromethane is
solvent extraction
decantation
fractional distillation
filtration
Correct answer is A
Solvent extraction, also known as liquid-liquid extraction, is a technique used to separate substances based on their differential solubilities in two immiscible liquids. In this case, since iodine and tetrachloromethane have different solubilities in certain solvents, you can use solvent extraction to selectively dissolve one of the substances while leaving the other behind. Iodine is a non-polar molecule, while tetrachloromethane is a polar molecule. This means that iodine will dissolve in a non-polar solvent, while tetrachloromethane will dissolve in a polar solvent
amphoteric
neutral
basic
acidic
Correct answer is C
Ethanoic acid is a weak acid, while sodium hydroxide is a strong base. When these two substances react, they neutralize each other, forming salt and water. The salt is a compound of the cation from the base and the anion from the acid. In this case, the salt is sodium ethanoate, which is a basic salt.
Which of the following equations does not illustrate correctly one of the reactions of chlorine?
\(Ca(OH)_2 + Cl_2 → CaOCl_2 + H_2O\)
\(Cl_2 + 2NaF → 2NaCl + F_2\)
\(Cl_2 + 2NaOH → NaCl + NaClO + H_2O\)
\(H_2S + Cl_2 → 2HCl + S\)
Correct answer is B
The equation \(Cl_2 + 2NaF → 2NaCl + F_2\) does not illustrate correctly one of the reactions of chlorine.
In this reaction, chlorine reacts with sodium fluoride to form sodium chloride and fluorine gas. However, this reaction is not possible because fluorine is a much more reactive element than chlorine. When chlorine and fluorine react, they form a compound called chlorine trifluoride (\(ClF_3)\), which is a very powerful oxidizing agent.