WAEC Mathematics Past Questions & Answers

$\begin{array}{c|c} & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline 1 & 1,1 & 1,2 & 1,3 & 1,4 & 1,5 & 1,6 \\ \hline 2 & 2,1 & 2,2 & 2,3 & 2,4 & 2,5 & 2,6 \\ \hline 3 & 3,1 & 3,2 & 3,3 & 3,4 & 3,5 & 3,6 \\ \hline 4 & 4,1 & 4,2 & 4,3 & 4,4 & 4,5 & 4,6 \\ 5 & 5,1 & 5,2 & 5,3 & 5,4 & 5,5 & 5,6 \\ \hline 6 & 6,1 & 6,2 & 6,3 & 6,4 & 6,5 & 6,6\end{array}$

From the table above, event space, n(E) = 6

sample space, n(S) = 36

Hence, probability sum of scores is at least 10, is;

$\frac{n(E)}{n(S)}$

= $\frac{6}{36}$

= $\frac{1}{6}$

344.

The figure is a pie chart which represents the expenditure of a family in a year. If the total income of the family was Le 10,800,000.00, how much was spent on food?

Le 2,250,000.00

Le 22,700,000.00

Le 3,600,000.00

Le 4,500,000.00

View answer & explanation

Correct answer is C

sectoral angle representing food

= 360^o - (80 + 70 + 90)^o

= 120^o

Amount spent on food

= $\frac{\tect{sectoral angle}}{360^o}$ x Le 10,800,000

= Le 3,600,000

345.

In the diagram, TX is perpendicular to UW, |UX| = 1cm and |TX| = |WX| = $\sqrt{3}$ cm. Find UTW

135^o

105^o

75^o

60^o

View answer & explanation

Correct answer is C

In $\Delta$ UXT, tan $\alpha$ = $\frac{1}{\sqrt{3}}$

$\alpha$ = tan^-1( $\frac{1}{\sqrt{3}}$ )

= 30^o

In $\Delta$ WXT, tan $\beta$ $\frac{\sqrt{3}}{\sqrt{3}}$ = 1

$\beta$ = tan^-1(1) = 45^o

Hence, < UTW = $\alpha$ + $\beta$

= 30^o + 45^o = 75^o