WAEC Mathematics Past Questions & Answers - Page 62

306.

Find the value of x for which \(\frac{x - 5}{x(x - 1)}\) is defined

A.

0 or 5

B.

-5 or 5

C.

-11 or 5

D.

0 or 1

Correct answer is A

The expression \(\frac{x - 5}{x(x - 1)}\) is defined whten

x(x - 5) = 0.38

either x = 0 or x - 5 = 0

Hence, x = 0 or x = 5

307.

The total surface area of a hemispher is 75\(\pi cm^2\). Find the radius.

A.

5.0 cm

B.

7.0 cm

C.

8.5 cm

D.

12.0 cm

Correct answer is A

Total surface area of hemisphere is

3\(\pi r^2\) = 75\(\pi cm^2\)

\(r^2\) = \(\frac{75 \pi}{3 \pi}\)

\(r^2\) = 25

r = \(\sqrt{25}\)

r = 5cm

308.

The table shows the distribution of goals scored by 25 teams in a football competition. Calculate the probability that a team selected at random scored at most 3 goals.

A.

\(\frac{3}{25}\)

B.

\(\frac{1}{5}\)

C.

\(\frac{6}{25}\)

D.

\(\frac{2}{5}\)

Correct answer is D

No. of teams that scored at most 3 goals = 3 + 1 + 6 = 10

Hence, probability that a team selected at random scored at most 3 goals

= \(\frac{10}{25}\) = \(\frac{2}{5}\)

309.

The table shows the distribution of goals scored by 25 teams in a football competition. Calculate the probability that a team selected at randon scored either 4 or 7 goals.

A.

\(\frac{9}{25}\)

B.

\(\frac{1}{5}\)

C.

\(\frac{6}{25}\)

D.

\(\frac{2}{5}\)

Correct answer is A

Prob. (team scored 4 goals) = Prob. (team scored 7 goals) = \(\frac{3}{25}\)

Hence, probability that a team selected at random scored either 4 or 7 goals;

= \(\frac{6}{25} + \frac{3}{25}\)

= \(\frac{9}{25}\)

310.

The mean of 1, 3, 5, 7 and x is 4. Find the value of x

A.

2

B.

4

C.

6

D.

8

Correct answer is B

Mean = \(\frac{\sum x}{n}\)

4 = \(\frac{1 + 3 + 5 + 7 + x}{5}\)

4 x 5 = 16 + x

20 - 16 = x

4 = x

x = 4