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WAEC Mathematics Past Questions & Answers - Page 58

286.

The solution of x + 2 2x + 1 is illustrated

A.

i

B.

ii

C.

iii

D.

iv

Correct answer is A

x + 2 2x + 1

x - 2x 1 - 2

-x -1

x1 11

x 1

287.

In the diagram, WXYZ is a rectangle with diamension 8cm by 6cm. P, Q, R and S are the midpoints of the rectangle as shown. Using this information calculate the area of the part of the rectangle that is not shaded

A.

25cm2

B.

24cm2

C.

16cm2

D.

12cm2

Correct answer is B

Area of shaded part = 2 x area of SPQ

= 2 x 12 8 x 3 =24cm

Hence, area of the unshaded part of the rectangle = area of rectangle - area of shaded part

= 8 x 6 - 24

= 48 - 24

= 24 cm2

288.

In the diagram, PS and RS are tangents to the circle centre O. ∠PSR = 70°, ∠POR = m, and ∠PSR =n. Find ( m + n ).

A.

110o

B.

135o

C.

165o

D.

225o

Correct answer is C

In the diagram,

 

Thus, m = 2 x 55o (is a bisector of obtuse

m = 110o

n = 12 x 110o (angle at centre = 2 x angle at circum)

n = 55o

m + n =  110 + 55 = 165o

 

290.

In the diagram, PR is a tangent to the circle at Q, QT//RS,

A.

40o

B.

65o

C.

85o

D.

95o

Correct answer is D

In the diagram,

a = 50o (alternate angles)

b1 + a 35o = 180o (sum of angles on a straight line)

i.e; b1 + 50o + 35o

= 180v

b1 + 180o - 85o = 90o

But b2 = b1 = 95o (angles in alternate segement)

<QST = b2 = 95o