Given that a = log 7 and b = \(\log\) 2, express log 35 in terms of a and b.
a + b + 1
ab - 1
a - b + 1
b - a + 1
Correct answer is C
\(\frac{\log 7 \times \log 10}{\log 2}\)
log 7 x log 10 \(\div\) log 2
a + 1 - b
a - b + 1
iii only
i and ii
ii and iii only
i, ii and iii
Correct answer is A
M = {3, 4, 5, 6, 7,}, N = {9, 10, 11, 12}
1 : 4
1 : 5
2 : 5
5 : 2
Correct answer is C
Tunde: Ola \(\to\) 1 : 2 ; Ola; Musa \(\to\) 4 : 5
\(\frac{1}{2}\) x \(\frac{4}{5}\)
= \(\frac{2}{5}\)
Evaluate \(\frac{3\frac{1}{4} \times 1\frac{3}{5}}{11\frac{1}{3} - 5 \frac{1}{3}}\)
\(\frac{14}{15}\)
\(\frac{13}{15}\)
\(\frac{4}{5}\)
\(\frac{11}{15}\)
Correct answer is B
\(\frac{3\frac{1}{4} \times 1\frac{3}{5}}{11\frac{1}{3} - 5 \frac{1}{3}}\) = \(\frac{\frac{26}{5}}{\frac{18}{3}}\) = \(\frac{26}{5} \div \frac{18}{3}\)
= \(\frac{13}{15}\)
If x varies inversely as y and y varies directly as z, what is the relationship between x and z?
x \(\alpha\) z
x \(\alpha\) \(\frac{1}{z}\)
a \(\alpha\) z\(^2\)
x \(\alpha\) \(\frac{1}{z^2}\)
Correct answer is B
\(x \propto \frac{1}{y}\), y \(\propto\) z
x = \(\frac{k}{y}\)
y = mz
Since y = mz,
x = \(\frac{k}{mz}\), where k and m are constants. Hence,
x \(\propto\) \(\frac{1}{z}\)