Solve: - \(\frac{1}{4}\) < \(\frac{3}{4}\) (3x - 2) < \(\frac{1}{2}\)
-\(\frac{5}{9}\) < x <\(\frac{8}{9}\)
-\(\frac{8}{9}\) < x <\(\frac{7}{9}\)
-\(\frac{8}{9}\) < x <\(\frac{5}{9}\)
-\(\frac{7}{9}\) < x <\(\frac{8}{9}\)
Correct answer is A
\(\frac{3}{4}\) (3x - 2) < \(\frac{1}{2}\); \(\frac{3}{4}\) (3x - 2) > - \(\frac{1}{4}\)
3(3x - 2) < 2; 3(3x - 2) > -1
9x - 6 < 2; 9x - 6 > -1
9x < 8; 9x > 5
x < \(\frac{5}{9}\); x > \(\frac{8}{9}\)
One factor of \(7x^2 + 33x - 10\) is
7x + 5
x - 2
7x - 2
x - 5
Correct answer is C
\(7x^2 + 33x - 10\)
\(7x^2 + 35x - 2x - 10\)
7x (x + 5) - 2 (x + 5)
(7x - 2) (x + 5)
N1,820.00
2,000.00
N2,020.00
N2,040.00
Correct answer is C
Let a girl's share = x + 20
4x + 5(x + 20) = 18,100
4x + 5x + 100 = 18,100
9x + 100 = 18,100
9x = 18,000
x = \(\frac{18,000}{9}\)
x = 2,000
\(\therefore\) Each boy gets N(2,000 + 20)
= N2,020.
Solve the equation: \(\frac{1}{5x} + \frac{1}{x}\)= 3
\(\frac{1}{5}\)
\(\frac{2}{5}\)
\(\frac{3}{5}\)
\(\frac{4}{5}\)
Correct answer is B
\(\frac{1}{5x} + \frac{1}{x}\)= 3
\(\frac{1 + 5}{5x}\) = 3
6 = 15x
x = \(\frac{6}{15}\)
= \(\frac{2}{5}\)
If x = \(\frac{2}{3}\) and y = - 6, evaluate xy - \(\frac{y}{x}\)
0
5
8
9
Correct answer is B
x = \(\frac{2}{3}\) and y = - 6
xy - \(\frac{y}{x}\)
\(\frac{2}{3} - (6)^2 - (-6) \div \frac{2}{3}\)
= -4 - (6) x \(\frac{3}{2}\)
= -4 - (-6) x \(\frac{3}{2}\)
= -4 - (-9)
= -4 + 9
= 5