decagon
nonagon
octagon
hexagon
Correct answer is C
Sum of all exterior angles is 360\(^o\)
360\(^o\) (30\(^o\) - 40\(^o\))
360 - (130\(^o\))
230\(^o\)
remaining is 46\(^o\) = \(\frac{230}{46}\) = 5
5 + 3 = 8 sides; Octagon
Simplify; \(\sqrt{2}(\sqrt{6} + 2\sqrt{2}) - 2\sqrt{3}\)
4
\(\sqrt{3} + 4\)
4 \(\sqrt{2}\)
4\(\sqrt{3} + 4\)
Correct answer is A
\(\sqrt{2}(\sqrt{6} + 2\sqrt{2}) - 2\sqrt{3}\)
\(\sqrt{12}\) + 2 x 2 - 2\(\sqrt{3}\)
2 \(\sqrt{3}\) - 2 \(\sqrt{3}\) + 4
= 4
In what number base was the addition 1 + nn = 100, where n > 0, done?
n - 1
n + 1
n
n + 2
Correct answer is C
No explanation has been provided for this answer.
10.1 years
9.3 years
8.7 years
8 . 3 years
Correct answer is A
x = 10 ; 10 = \(\frac{x}{25}\)
x = 250
x = \(\frac{250 + 12.4}{26}\)
x = 10.09
x = 10.1 years
\(\sqrt{3 - 2}\)
2 - \(\sqrt{3}\)
\(\sqrt{3}\)
-2
Correct answer is C
Tan 60 = 3; Tan 30 = 1
\(\frac{\tan 60^o - 1}{1 - tan 30^o}\) = \(\frac{\sqrt{3 - 1}}{1 - \frac{1}{\sqrt{3}}}\) = \(\frac{\sqrt{3 - 1}}{\frac{3 - 1}{\sqrt{3}}}\)
= \(\frac{\sqrt{3 - 1}}{1} \times \frac{\sqrt{3 - 1}}{\sqrt{3}}\)
= \(\frac{\sqrt{3 - 1}}{1} \times \frac{\sqrt{3}}{\sqrt{3}}\)
= \(\sqrt{3}\)