Find the 8th term of the A.P -3, -1, 1 ......
13
11
-8
-11
-17
Correct answer is B
Un = a + (n-1)d
= -3 + (8 - 1)2
= 11
Simplify 36\(^\frac{1}{2}\) x 64\(-^\frac{1}{3}\) x 5\(^0\)
0
1\24
2/3
11/2
71/2
Correct answer is D
36\(^\frac{1}{2}\) x 64\(-^\frac{1}{3}\) x 5\(^0\)
= \(6 \times \frac{1}{4} \times 1\)
= \(1\frac{1}{2}\)
Express the product of 0.06 and 0.09 in standard form
5.4 * 10-1
5.4*10-2
5.4*10-3
5.4*102
5.4*103
Correct answer is C
0.06 x 0.09 = 0.0054
= 5.4 x 10-3
1
2.02
20.02
202
2020
Correct answer is D
(101.5)2 - (100.5)2;(101.5 + 100.5)
202 x 1
= 202
If sin\( \theta \) = K find tan\(\theta\), 0° \(\leq\) \(\theta\) \(\leq\) 90°.
1-K
\( \frac{k}{k - 1} \)
\( \frac{k}{\sqrt{1 - k^2}} \)
\( \frac{k}{1 - k} \)
\( \frac{k}{\sqrt{ k^2 - 1}} \)
Correct answer is C
\(\sin \theta = \frac{k}{1}\)
\(\implies 1^2 = k^2 + adj^2\)
\(adj = \sqrt{1 - k^2}\)
\(\therefore \tan \theta = \frac{k}{\sqrt{1 - k^2}}\)