x = 1
x = -1
y = 1
y = -1
x + y = 1
Correct answer is C
The linear equation will be the difference between the equation.
y=x2 + 4x - 6 and x2 + 4x - 7 = 0
y=x2 + 4x - 6, ( 0 = x2 + 4x - 7)
y = -(-1) y = 1
If sinθ = 3/5 find tanθ for 0 < θ < 90o
4\5
3\4
5\8
1\2
3\8
Correct answer is B
sinθ = 3/5
tanθ = 3/4
16o
17o
73o
106o
164o
Correct answer is E
Using pythagoras' theorem:
Hyp\(^2\) = Adj\(^2\) + Opp\(^2\) → 24\(^2\) + 7\(^2\)
Hyp = √625 → 25
\(\tan P = \frac{7}{24}\)
\(\tan P = 0.2917\)
\(P = \tan^{-1} (0.2917)\)
= 16.26°
Bearing of Q from P = 180° - 16.26°
= 163.74° \(\approxeq\) 164°
Points P and Q respectively 24m north and 7m east point R. Calculate |PQ| in meters
20
24
25
31
84
Correct answer is C
No explanation has been provided for this answer.
I & III only
I & IV only
II & III only
II & IV only
All of the above
Correct answer is C
No explanation has been provided for this answer.