The area of a parallelogram is 513cm\(^2\) and the height is 19cm. Calculate the base.
13.5cm
25cm
27cm
54cm
108cm
Correct answer is C
Area of parallelogram = base \(\times\) height.
\(513 = base \times 19 \implies base = \frac{513}{19}\)
= 27 cm
The volume of a cone of height 9cm is 1848cm\(^3\). Find its radius. [Take π = 22/7]
7cm
14cm
28cm
98cm
196cm
Correct answer is B
1/3 πr\(^2\) x 9 = 1848
3 x πr2 = 1848 r2 = 1848/3 x 7/22 r = 14
\(\text{Volume of a cone} = \frac{1}{3} \pi r^2 h\)
\(\frac{1}{3} \times \frac{22}{7} \times r^2 \times 9 = 1848\)
\(r^2 = \frac{1848 \times 7}{22 \times 3}\)
\(r^2 = 196 \therefore r = 14cm\)
3.5cm
7cm
14cm
28cm
32cm
Correct answer is C
Curved surface area of a cylindrical tin = \(2\pi rh\)
\(\therefore 2\pi rh = 704cm^2\)
\(2 \times \frac{22}{7} \times 8 \times h = 704\)
\(h = \frac{704 \times 7}{2 \times 22 \times 8}\)
\(h = 14cm\)
16/3cm
15/3cm
16/5cm
8/3cm
16/10cm
Correct answer is A
L = θ/360 x 2πR = 240/360 x 2 x 22/7 x 8/1 ... (1)
This must be equal to the circumference of the circle which is 2πr = 44R/7 .... (2)
equate (1) and (2)
r = 16/3 = 51/3
Solve the equation \(\frac{m}{3} + \frac{1}{2} = \frac{3}{4} + \frac{m}{4}\)
-3
-2
2
3
4
Correct answer is D
\(\frac{m}{3} + \frac{1}{2} = \frac{3}{4} + \frac{m}{4}\)
\(\frac{m}{3} - \frac{m}{4} = \frac{3}{4} - \frac{1}{2}\)
\(\frac{m}{12} = \frac{1}{4}\)
\(4m = 12 \implies m = 3\)