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WAEC Mathematics Past Questions & Answers - Page 301

1,501.

The volume of a cone of height 9cm is 1848cm3. Find its radius. [Take π = 22/7]

A.

7cm

B.

14cm

C.

28cm

D.

98cm

E.

196cm

Correct answer is B

1/3 πr2 x 9 = 1848
3 x πr2 = 1848 r2 = 1848/3 x 7/22 r = 14

Volume of a cone=13πr2h

13×227×r2×9=1848

r2=1848×722×3

r2=196

1,502.

The curved surface area of a cylindrical tin is 704cm^2. Calculate the height when the radius is 8cm. [Take π = 22/7]

A.

3.5cm

B.

7cm

C.

14cm

D.

28cm

E.

32cm

Correct answer is C

Curved surface area of a cylindrical tin = 2\pi rh

\therefore 2\pi rh = 704cm^2

2 \times \frac{22}{7} \times 8 \times h = 704

h = \frac{704 \times 7}{2 \times 22 \times 8}

h = 14cm

1,503.

The angle of a sector of a circle of radius 8cm is 240°. This sector is bent to form a cone. Find the radius of the base of the cone.

A.

16/3cm

B.

15/3cm

C.

16/5cm

D.

8/3cm

E.

16/10cm

Correct answer is A

L = θ/360 x 2πR = 240/360 x 2 x 22/7 x 8/1 ... (1)

This must be equal to the circumference of the circle which is 2πr = 44R/7 .... (2)

equate (1) and (2)

r = 16/3 = 51/3

1,504.

Solve the equation \frac{m}{3} + \frac{1}{2} = \frac{3}{4} + \frac{m}{4}

A.

-3

B.

-2

C.

2

D.

3

E.

4

Correct answer is D

\frac{m}{3} + \frac{1}{2} = \frac{3}{4} + \frac{m}{4}

\frac{m}{3} - \frac{m}{4} = \frac{3}{4} - \frac{1}{2}

\frac{m}{12} = \frac{1}{4}

4m = 12 \implies m = 3

1,505.

What must be added to the expression x^2 - 18x to make it a perfect square?

A.

3

B.

9

C.

36

D.

72

E.

81

Correct answer is E

x^2 - 18x to be a perfect square.

(\frac{b}{2})^2 is added to ax^2 + bx + c in order to make it a perfect square.

x^2 - 18x + (\frac{-18}{2})^2

= x^2 - 18x + 81