WAEC Mathematics Past Questions & Answers - Page 283

1,411.

Which of the following is a root of the equation x\(^2\) +6x = 0?

A.

0

B.

1

C.

2

D.

3

E.

It does not have any root.

Correct answer is A

\(x^2 + 6x = 0\)

\(x(x + 6) = 0\)

\(x = 0\) or \(x = -6\)

1,412.

Find the quadratic equation whose roots are 3 and \(\frac{2}{3}\).

A.

x2 - 11 / 3x + 6 = 0

B.

x2 - 11x + 6 = O

C.

3x2 - 11x + 2 = O

D.

3X2 - 11x – 2 = 0

E.

3x2 - 11x + 6 = 0

Correct answer is E

x = 3; x = \(\frac{2}{3}\).

(x - 3)(x - \(\frac{2}{3}\)) = 0

\(x^2 - \frac{2x}{3} - 3x + 2 = 0\)

\(x^2 - \frac{11x}{3} + 2 = 0\)

\(3x^2 - 11x + 6 = 0\)

1,413.

Which of the following is not a factors of 2p\(^2\) - 2?

A.

2

B.

p - 1

C.

p + 1

D.

2p - 2

E.

2p + 1

Correct answer is E

2p\(^2\) - 2 

2(p\(^2\) - 1)

= 2(p + 1)(p - 1)

1,414.

Which of the following equations can be solved by the points of intersection P and Q of the curve and the line PQ?

A.

x2 - 2 = 0

B.

x2 - 4 = 0

C.

x2 + 6 = 0

D.

X2 - X – 2 = 0

E.

x2 - x + 4 = 0

Correct answer is B

The points of intersection of the curve and the line are at x = -2 and x = 2.

\(\therefore\) (x + 2) = 0; (x - 2) = 0.

(x + 2)(x - 2) = 0

\(x^2 - 4 = 0\)

1,415.

What is the equation of the line PQ?

A.

y = x - 5

B.

y = x + 3

C.

y = x + 5

D.

y = 2x + 3

E.

y = 2x - 3

Correct answer is C

The points P(-2, 3) and Q(2, 7) are on the line.

Gradient of the line = \(\frac{7 - 3}{2 - (-2)}\)

= \(\frac{4}{4}\)

= 1

y = x + b

To find the intercept, we have

7 = 2 + b or 3 = -2 + b.

Solving for b, we get b = 5.

\(\therefore\) The line is y = x + 5.