\(\frac{√21}{21}\)
7\(\frac{√21}{21}\)
\(\frac{√21}{3}\)
3√21
Correct answer is C
2√7- 14/√7 +7/√21
L.C.M is √21
\(\frac{√21 * 2√7 - √3 *14 + 7}{√21}\)
=\(\frac{2 * 7√3 - 14√3 + 7}{√21}\)
= \(\frac{14√3 - 14√3 + 7}{√21}\)
=\(\frac{7}{√21}\)
or
\(\frac{7 \times √21}{√21 \times √21}\)
= \(\frac{7 \times √21}{21}\) or \(\frac{√21}{3}\)
5km
6km
7km
3km
Correct answer is A
Circumference of the circular track = 9km
Distance covered = 302km
Number of complete circles or revolutions from the starting point = 302/9 =33 circles and additional 5km.
So, the distance of the cyclist from the starting point would be 5km
If 16 * 2\(^{(x + 1)}\) = 4\(^x\) * 8\(^{(1 - x)}\), find the value of x.
-4
4
1
-1
Correct answer is D
16 * 2\(^{(x + 1)}\) = 4\(^x\) * 8\(^{(1 - x)}\)
= 2\(^4\) * 2\(^{(x + 1)}\) = 2\(^{2x}\) * 2\(^{3(1 - x)}\)
--> 4 + x + 1 = 2x + 3 - 3x
collect like terms
--> x - 2x + 3x = 3 - 1 - 4
--> 2x = -2
--> x = -1
if p = {-3<x<1} and Q = {-1<x<3}, where x is a real number, find P n Q.
0
-3, -2, -1, 0 and 1
-2, -1 and 0
-1, 0 and 1
Correct answer is A
p = {-3<x<1} = {-2,-1 and 0}
Q = {-1<x<3} = {0,1 and 2}
P n Q = {0} or {-1<x<1}
Find the least value of x which satisfies the equation 4x = 7(mod 9)
7
6
5
4
Correct answer is D
4x = 7 (mod 9)
4x = 7 + 9 (mod 9)
\(\frac{4x}{4} = \frac{16}{4}\) (mod 9)
x = 4