In the diagram, O is the centre of the circle PQRS, ∠PQR = 72° and OR is parallel to PS. Find ∠ OPS.
18°
108°
54°
36°
Correct answer is D
Angle at the centre O is twice the angle at the circumference.
i.e O = 72° * 2 = 144°
∠OPS = 180 - 144 = 36°
225°
315°
045°
135°
Correct answer is C
No explanation has been provided for this answer.
Which of the following is not an exterior angle of a regular polygon?
66°
72°
24°
15°
Correct answer is A
No explanation has been provided for this answer.
In the diagram, △XYZ is produced to T. if |XY| = |ZY| and ∠XYT = 40°, find ∠XZT
110°
130°
140°
180°
Correct answer is A
Isosceles Triangle. Two equal sides. Two equal angles ;
∠ X = ∠ Z
∠Y + ∠X + Z = 180 --> 40° + ∠X + ∠X = 180°
∠2X = 180° - 40° = 140°
∠X = 70°, i.e ∠X = 70 and ∠Z = 70°.
The exterior angle of triangle is the sum of two opposite internal angles
: ∠X + ∠Y = ∠XZT
=70° + 40° = 110°
The diagonal of a rhombus are 12cm and 5cm. calculate its perimeter
26cm
24cm
17cm
34cm
Correct answer is A
Perimeter of a Rhombus = 4L or 2√( d1\(^2\) + d2\(^2\))
P = 2√(12\(^2\) + 5\(^2\))
P = 2√(144 + 25)
P = 2√169 = 2 * 13
P = 26cm
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