| Height(cm) | 160 | 161 | 162 | 163 | 164 |
165 |
| No. of players | 4 | 6 | 3 | 7 | 8 | 9 |
the table shows the height of 37 players of a basketball team calculates correct to one decimal place the mean height of the players.
163.0
162.0
160.0
165.0
Correct answer is A
∑fx = (160 * 4) + (161 * 6) + (162 * 3) + (163 * 7) + (164 * 8) + (165 * 9)
=640 + 966 + 486 + 1,141 + 1,312 + 1,485
= 6,030
∑f = 4 + 6 + 3 + 7 + 8 + 9
= 37
= \(\frac{∑fx}{∑f}\)
= \(\frac{6030}{37}\)
= 162.97 or 163
112
90
68
22
Correct answer is C
No explanation has been provided for this answer.
Given that sin x = 3/5, 0 ≤ x ≤ 90, evaluate (tanx + 2cosx)
2\(\frac{11}{20}\)
\(\frac{11}{20}\)
2\(\frac{7}{20}\)
\(\frac{1}{20}\)
Correct answer is B
Sin x = \(\frac{opp}{hyp}\)
sinx = \(\frac{3}{5}\)
using Pythagoras' theorem
hyp\(^2\) = opp\(^2\) + adj\(^2\)
adj\(^2\) = 5\(^2\) - 3\(^2\) = 25 - 9
adj\(^2\) = 16
adj = √ 16
adj = 4.
tanx = \(\frac{opp}{adj}\)
= \(\frac{3}{4}\)
cosx = \(\frac{adj}{hyp}\)
= \(\frac{4}{5}\)
(tanx + 2cosx) = \(\frac{3}{4}\) + 2(\(\frac{4}{5}\))
= \(\frac{15 + 32}{20}\)
= \(\frac{47}{20}\) or
2 \(\frac{7}{20}\)
341.98cm\(^2\)
276.57cm\(^2\)
201.14cm\(^2\)
477.71cm\(^2\)
Correct answer is A
Where l\(^2\) = h\(^2\) + r\(^2\)
l\(^2\) = 11\(^2\) + 8\(^2\)
l = √185
l = 13.60cm
The formula of CSA of Cone is πrl
\(\frac{22}{7}\) * 8 * 13.60
= 341.979 or 341.98 (2d.p)
In the diagram, PQRS is a circle. find the value of x.
50°
30°
80°
100°
Correct answer is A
Opp. angles in a cyclic quadrilateral always add up to 180°
∠P + ∠R & ∠Q + ∠S = 180
x + x+y = 180
2x + y = 180... i
2y - 30 + x = 180
2y + x = 180 + 30
x + 2y = 210 ... ii
Elimination method:
(2x + y = 180) * 1 --> 2x + y = 180
(x + 2y = 210) * 2 --> 2x + 4y = 420
Subtracting both equations
- 3y = - 240
y = 80°
using eqn i
2x + y = 180
2x + 80 = 180
2x = 100
x = 50°
WAEC Subjects
Aptitude Tests