WAEC Mathematics Past Questions & Answers - Page 211

1,051.

The variance of a given distribution is 25. What is the standard deviation?

A.

125

B.

75

C.

25

D.

5

Correct answer is D

S.D = \(\sqrt{Variance}\)

= \(\sqrt{25}\)

= 5

1,052.

Simplify \(5\frac{1}{4}\div \left(1\frac{2}{3}- \frac{1}{2}\right)\)

A.

\(1\frac{3}{4}\)

B.

\(3\frac{1}{2}\)

C.

\(4\frac{1}{2}\)

D.

\(8\frac{1}{2}\)

Correct answer is C

\(5\frac{1}{4}\div \left(1\frac{2}{3}- \frac{1}{2}\right)\\
\frac{21}{4}\div \left(1\frac{4-3}{6}\right)\\
\frac{21}{4}\div \left(1\frac{1}{6}\right)\\
\frac{21}{4} \times \frac{6}{7}= 4\frac{1}{2}\)

1,053.

In the diagram above, ∠PQU=36°, ∠QRT = 29°, PQ||RT. Find ∠PQR

A.

94o

B.

65o

C.

61o

D.

54o

Correct answer is B

< UQR = 29° (alternate angles)

< PQR = < PQU + < UQR

= 36° + 29°

= 65°

1,054.

PQRS is a trapezium in which |PS| = 9cm, |QR| = 15cm, |PQ| = \(2\sqrt{3}, \angle PQR = 90^o and \angle QRS = 30^o\). Calculate the area of the trapezium

A.

\(24\sqrt{3} cm^2\)

B.

\(36\sqrt{3} cm^2\)

C.

\(42\sqrt{3} cm^2\)

D.

\(72\sqrt{3} cm^2\)

Correct answer is A

No explanation has been provided for this answer.

1,055.

A solid cylinder of radius 7cm is 10 cm long. Find its total surface area.

A.

\(70\pi cm^2\)

B.

\(189\pi cm^2\)

C.

\(210\pi cm^2\)

D.

\(238\pi cm^2\)

Correct answer is D

S = \(2\pi r^2 + 2\pi rh\)

= \(2\pi r(r + h)\)

= \(2\pi (7) (7 + 10)\)

= \(238\pi cm^2\)