47cm
61cm
88cm
231cm
Correct answer is B
Perimeter of the sector = 2r+θ360×2πr
= 2(14)+135360×2×227×14
= 28+33
= 61 cm
9πcm2
15πcm2
16πcm2
20πcm2
Correct answer is B
Curved surface area or a cone =πrl
from the information l^2 = 4^2 + 3^2 = 16+9\\
l = \sqrt{25} = 5; ∴ C.S.A\hspace{1mm} = \frac{22}{7}\times 3 \times 5\\
Since \frac{22}{7}=\pi ∴ C.S.A\hspace{1mm} =\hspace{1mm}15\pi
5\frac{1}{3}cm^3
10\frac{2}{3}cm^3
16cm^3
32cm^3
Correct answer is B
No explanation has been provided for this answer.
8m
9m
10m
13m
Correct answer is A
Given, Length of minor arc = 5.5m
Angle subtended by minor arc = 360° - 210° = 150°
\therefore 5.5 = \frac{150}{360} \times 2 \times \frac{22}{7} \times r
\frac{55r}{21} = 5.5
r = \frac{5.5 \times 21}{55}
r = 2.1m
Length of major arc = \frac{210}{360} \times 2 \times \frac{22}{7} \times 2.1
= 7.7m \approxeq 8m (to the nearest metre)
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