In the diagram, SQ is a tangent to the circle at P, XP||YQ, ∠XPY = 56o and ∠PXY = 80o.Find angle PQY
34o
13.36o
44o
46o
Correct answer is A
< XYQ = 180° - (80° + 56°)
= 44°
< PYQ = 56° (alternate angles, XP||YQ)
< QPY = 90°
< PQY = 180° - (90° + 56°)
= 34°
Which of the following is represented by the above sketch?
y = x2 + x - 6
y = x2 - x - 6
y = x2 - x + 6
y = x2 + x + 6
Correct answer is B
From the graph, the zeros of the equation exist at x = -2 and x = 3
\(\therefore\) (x + 2) = 0 and (x - 3) = 0
\(\implies (x + 2)(x - 3) = 0\)
\(x^2 - 3x + 2x - 6 = 0\)
\(x^2 - x - 6 = 0\) is the equation represented on the graph.
If (-3, -4) is a point on the line y = mx + 2 find the value of m.
-2
\(\frac{7}{4}\)
2
\(\frac{8}{3}\)
Correct answer is C
If (-3, -4) is a point on the line then
-4 = -3m + 2
-4 - 2 = -3m
-6 = -3m
m = 2
Find the nth term of the sequence 4, 10, 16 ,...
2(3n- 1)
2(2 + 3 n-1)
2 n + 2
2(3n+2)
Correct answer is A
\(T_{1} = 4; T_2 = 10; T_3 = 16\)
\(T_{2} - T_1 = T_3 - T_1 = 6\)
\(T_n = a + (n - 1) d\)
= \(4 + (n - 1) \times 6\)
= \(4 + 6n - 6\)
= \(6n - 2\)
= 2(3n - 1)
From the diagram, find the bearing of Q from P.
236o
214o
146o
124o
Correct answer is A
No explanation has been provided for this answer.
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