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WAEC Mathematics Past Questions & Answers - Page 196

976.

Correct answer is A

Sum of interior angle of the diagram equals 360^o
180^o - 5y^o + 136^o + 180^o + 180^o - 3y^o = 360^o
-8y^o + 136^o = 0
-8y^o = -136; y = 17

977.

The four interior angles of a quadrilateral are (x + 20) ^o, (x+ 10) ^o (2x - 45) ^o and (x - 25) ^o. Find the value of x

100

360

View answer & explanation

Correct answer is B

Sum of interior angles in a quadrilateral is 360
(x + 20)^o + (x+ 10)^o + (2x - 45)^o + (x - 25)^o = 360^o
5x^o - 40^o = 360^o
x = 400/5 = 80^o

978.

What is the size of angle x in the diagram

15^o

30^o

45^o

60^o

View answer & explanation

Correct answer is B

$Sin\theta^{\circ} = \frac{opp}{hyp}\\ Sin X^{\circ}=\frac{5}{10}=0.5000\\SinX^{\circ}\\ X^{\circ} = sin^{-1}0.5000\\ X^{\circ}=30^{\circ}$

979.

A ladder, 6m long, leans against a vertical wall at an angle 53^o to the horizontal. How high up the wall does the ladder reach?

3.611m

4.521m

4.792m

7.962m

View answer & explanation

Correct answer is C

Sin 53 = $\frac {h}{6}$
h = 6 sin 53 = 6 x 0.7986
= 4.792m

980.

Given, that $4P4_5 = 119_{10}$ , find the value of P

View answer & explanation

Correct answer is C

$4P4_5 = 119_{10}$

$4 \times 5^2 + P \times 5^1 + 4 \times 5^0 = 119$

$100 + 5P + 4 = 119$

$5P = 119 - 104 = 15$

$P = 3$

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