The bearing of P from Q is x, where 270o < x < 360o. Find the bearing of Q from P
(x - 90)o
(x-270)o
(x - 135)o
(x - 180)o
Correct answer is D
Bearing of Q and P
\(180^{\circ} – (360^{\circ}-x)\\
180^{\circ}-360^{\circ}+x\\
-180^{\circ}+x\\
x-180^{\circ}\)
A man made a loss of 15% by selling an article for N595. Find the cost price of the article
N600.00
N684.25
N700.00
N892.50
Correct answer is C
15% loss = N595
\(\implies\) (100 - 15)% of CP = N595
85% of CP = N595
CP = \(\frac{595 \times 100}{85}\)
= N700.00
A right circular cone is such that its radius r is twice its height h. Find its volume in terms of h
\(\frac{2}{3}\pi h^2\)
\(\frac{1}{12}\pi h^3\)
\(\frac{4}{3}\pi h^2\)
\(\frac{4}{3}\pi h^3\)
Correct answer is D
Volume of a cone = \(\frac{\pi r^2 h}{3}\)
r = 2h.
V = \(\frac{\pi \times (2h)^2 \times h}{3}\)
= \(\frac{4}{3} \pi h^3\)
55cm2
25cm2
22cm2
13cm2
Correct answer is A
Considering the triangle in the diagram
\(tan\theta = \frac{opp}{hyp}\\
Tan 63^{\circ} = \frac{h}{4}\\
h = 4 tan 63^{\circ}\\
Area of trapezium = \frac{1}{2}h(a+b)\\
\left(\frac{1}{2} \times 4 tan 63^{\circ}[5+9]\right)\\
=28\times 1.963 = 54.96 = 55cm^2\)
90o
75o
60o
45o
Correct answer is C
No explanation has been provided for this answer.
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