Solve the simultaneous equation: x+y=2 and 3x-2y=1
x=2 and y=1
x=1 and y=1
x=1 and y=2
x=-1 and y=1
Correct answer is B
x + y = 2 --- eqn I
3x - 2y = 1 --- eqn II
Multiply eqn by 2
2x + 2y = 2 --- eqn III
Subtract eqn II from eqnI
5x = 5 => x = 1
Substitute 1 for x in eqn 1
1 + y = 2 => y = 1
If x =3, y = 2 and z = 4 what is the value of \(3x^{2}-2y+z\)
17
27
35
71
Correct answer is B
\(3x^{2}-2y+z=3(3)^{2}-2(2)+4=27-4+4=27\)
For what value of x is the expression \(\frac{2x-1}{x+3}\)not defined?
3
2
1/2
-3
Correct answer is D
x + 3 = 0 => x = -3
I am x years old and my brother is 3 years older how old was my brother last year
(x - 4) years
(x + 2) years
(3x - 1) years
(3x + 1) years
Correct answer is B
If I am x years old, then my brother will be (x + 3)years old then last year my brother was (x + 3) - 1 = (x + 2)years old
N80,000
N40,000
N20,000
N10,000
Correct answer is B
\(Abu = 2x\\
Kayode = x\\
Uche = \frac{x}{2}\\
2x+x+\frac{x}{2}=140,000\\
\frac{7x}{2}=140,000\\
7x = 280,000\\
x=\frac{280,000}{7}\\
x=40,000\)Kayode receives N40,000