WAEC Mathematics Past Questions & Answers - Page 152

756.

The venn diagram shows the choice of food of a number of visitors to a canteen. If there were 35 visitors in all, find the value of x

View answer & explanation

Correct answer is A

5 + 6 + 4 + 8 + 5 + 2 + x = 35

30 + x = 35

x = 35 - 30

x = 5

757.

Find the value of x in the diagram

281^o

269^o

201^o

179^o

View answer & explanation

Correct answer is A

a = 34^o (alternate angles)

b = 45^o (alternate ngles)

a + b = 34 + 45 = 79^o

x + 79 = 360(sum of angles at a point)

x = 360 - 79

x = 281^o

758.

In the diagram, |SP| = |SR| and < PRS = 50^o. Calculate < PQR

120^o

110^o

100^o

80^o

View answer & explanation

Correct answer is C

< PRS = RPS = 50^o (base of isosceles)

RPS = 50^o; < RSP + < PRS + < RPS = 180(sum of < s in a triangle)

< RPS + 50 + 50 = 180

< RSP = 180 - 100 = 80

then < PQR + < RSp = 180 (opp. < S of cyclic quad.)

< PQR + 80 = 180^o

< PQR = 180 - 80

= 100

759.

From the diagram, find the value of x in the diagram.

80^o

70^o

55^o

35^o

View answer & explanation

Correct answer is B

y + 110^o = 180^o(angles on a straight line)

y = 180 - 110

= 70^o

x = y(corresponding angles)

x = 70^o

760.

In the diagram |LN| = 4cm, LNM = 90^o and tan y = \(\frac{2}{3}\). What is the area of the \(\bigtriangleup\)LMN?

24cm²

12cm²

10cm²

6cm²

View answer & explanation

Correct answer is B

Since tan y = \(\frac{2}{3}\) and LN = 4

tan y = \(\frac{2 \times 4}{3 \times 4} = \frac{8}{12} = \frac{4}{6}\)

then tan y = \(\frac{opp}{adj}\)

MN = 6cm

Area of angle LMN = \(\frac{1}{2}\)bh

= \(\frac{1}{2} \times 6 \times 4\)

= 12cm³