In the diagram, |SP| = |SR| and < PRS = 50o. Calculate < PQR
120o
110o
100o
80o
Correct answer is C
< PRS = RPS = 50o (base of isosceles)
RPS = 50o; < RSP + < PRS + < RPS = 180(sum of < s in a triangle)
< RPS + 50 + 50 = 180
< RSP = 180 - 100 = 80
then < PQR + < RSp = 180 (opp. < S of cyclic quad.)
< PQR + 80 = 180o
< PQR = 180 - 80
= 100
From the diagram, find the value of x in the diagram.
80o
70o
55o
35o
Correct answer is B
y + 110o = 180o(angles on a straight line)
y = 180 - 110
= 70o
x = y(corresponding angles)
x = 70o
In the diagram |LN| = 4cm, LNM = 90o and tan y = 23. What is the area of the △LMN?
24cm2
12cm2
10cm2
6cm2
Correct answer is B
Since tan y = 23 and LN = 4
tan y = 2×43×4=812=46
then tan y = oppadj
MN = 6cm
Area of angle LMN = 12bh
= 12×6×4
= 12cm3