Find the quadratic equation whose roots are -12 and 3
2x2 - 2x + 3 = 0
2x2 - 2x - 3 = 0
2x2 - 5x - 3 = 0
3x2 - 5x - 3 = 0
Correct answer is C
x = −12
x = 3
2x = -1, x = 3; 2x + 1 = 0
x - 3 = 0
(2x + 1)(x - 3) = 0
2x2 - 6x + x - 3 = 0
2x2 - 5x - 3 = 0
Simplify (x - 3y)2 - (x + 3y)2
2(x + 3y)
(2x - 3y)
-12xy
6xy
Correct answer is C
(x - 3y)2 - (x + 3y)2 = [(x - 3y) - (x + 3y)]
[(x + 3y + x + 3y)] = [-6y] [2x]
= -12xy
it is a scalene triangle
it is right angled isosceles triangle
it is an equilateral triangle
It is an isosceles triangle but not right angled
Correct answer is C
(x + 10)o + (2x - 40)o + (3x - 90)o = 180
6x - 120 = 180
6x = 180 + 120
6x = 300
x = 3006
x = 50
x + 10o = 50o + 10o = 60o
2x - 40 = 2(50o) - 40 = 60o
3x - 90 = 3(50o) - 90o = 60o
Hence, it is an equilateral triangle
zero
√2
2√2
4\(\sqrt{2}\0
Correct answer is A
12√32−√18√2 = 12(4√2)−3√2+√2
= 2√2−3√2+√2
= 3√2−3√2−3√2 = 0
3
7
9
12
Correct answer is C
Total no of balls = 30
Let x = no. of red balls
Pr(red) = x30
Pr(black) = 310=930
Pr(white) = 25=1230
No. of black balls = 9
No. of white balls = 12
9 = 12 + x = 30
x = 30 - 21
x = 9
No. of red balls = 9