WAEC Mathematics Past Questions & Answers - Page 135

671.

PQRS is a trapezium. QR//PS, /PQ/ = 5cm, /OR/ = 6cm, /PS/ = 10cm and angle QPS = 42o. Calculate, correct to the nearest cm2, the area of the trapezium (h = 3.35cm2 )

A.

27cm2

B.

30cm2

C.

36cm2

D.

37cm2

Correct answer is A

Area = \(\frac{1}{2}(a + b)\)h

where a = QR = 6cm

b = PA = 10cm

Area = \(\frac{1}{2}(6 + 10)\) x 3.35cm2

= \(\frac{1}{2}(16)\) x 3.35cm2

= 26.8cm2

= 27cm2 (approx.)

672.

PQRS is a trapezuim. QR//PS, /PQ/ = 5cm, /OR/ = 6cm, /PS/ = 10cm and angle QPS = 42o. Calculate the perpendicular distance between the parallel sides

A.

3.35cm

B.

3.73cm

C.

4.50cm

D.

4.62cm

Correct answer is A

h = ?

\(\frac{h}{5cm}\) = sin 45o

h = 5cm x 0.6691 = 3.35cm

673.

The following is the graph of a quadratic friction, find the value of x when y = 0

A.

1, 2

B.

1, 4

C.

2, 3

D.

1, 6

Correct answer is B

when y = 0, value of x = roots of the equation

x2 - 5x + 4 = 0

x = 1, 4 (see graph)

674.

The following is the graph of a quadratic friction, find the co-ordinates of point P

A.

(0, 4)

B.

(4, 0)

C.

(0, -4)

D.

(-4, 0)

Correct answer is A

No explanation has been provided for this answer.

675.

Find the quadratic equation whose roots are -\(\frac{1}{2}\) and 3

A.

2x2 - 2x + 3 = 0

B.

2x2 - 2x - 3 = 0

C.

2x2 - 5x - 3 = 0

D.

3x2 - 5x - 3 = 0

Correct answer is C

x = \(\frac{-1}{2}\)

x = 3

2x = -1, x = 3; 2x + 1 = 0

x - 3 = 0

(2x + 1)(x - 3) = 0

2x2 - 6x + x - 3 = 0

2x2 - 5x - 3 = 0