WAEC Mathematics Past Questions & Answers - Page 107

531.

Is the diagram, MN, PQ and RS are three intersecting straight lines. Which of the following statements is/are true? i. t = y ii. x + y + z + m = 180o iii. x + m + n = 180o iv. x + n = m + z

A.

i and iv

B.

ii

C.

iii

D.

iv

Correct answer is C

m + y + x = 180o(sum of < s on straight line)

y = n(vertically opp. angle)

m + n + x = 180o

532.

In the diagram, MQ//RS, < TUV = 70o and < RLV = 30o. Find the value of x

A.

150o

B.

110o

C.

100o

D.

95o

Correct answer is C

L + 30o - 180o(Sum of < s on straight line)

L = 180o - 30o = 150o

L = q = 150o(opposite < s are equal)

y = b = 30o(alt. < s)

b + c = 180o(sum of < s on str. line)

30o + c 180

c = 180 - 30

c = 150o

b = a = 30o (opp < s are equal)

c = d = 150o (opp < s are equal)

a + k + 70o = 180o (sum of < s on \(\bigtriangleup\))

30o + k + 70o = 180

k + 100o = 180

k = 180 - 100

k = 80o

x + 80o = 180(sum of < s on straight line)

x = 180o - 80o

x = 100o

533.

The diagram is a circle centre O. If < SPR = 2m and < SQR = n, express m in terms of n

A.

m = \(\frac{n}{2}\)

B.

m = 2n

C.

m = n - 2

D.

m = n + 2

Correct answer is A

If < SPR = 2m then < SQR = 2m but < AQR was n

n = 2m

m = \(\frac{n}{2}\)

534.

In the diagram, O is a circle centre of the circle PQRS and < PSR = 86o. If < PQR = xo, find x

A.

108o

B.

172o

C.

130o

D.

50o

Correct answer is B

No explanation has been provided for this answer.

535.

In the diagram, |QR| = 10m, |SR| = 8m

< QPS = 30o, < QRP = 90o and |PS| = x, Find x

A.

1.32m

B.

6.32m

C.

9.32m

D.

17.32

Correct answer is C

In right angled \(\bigtriangleup\)QPR

tan 30o = \(\frac{10}{x + 8}\)

(x + 8) tan 30 = 10

x + 8 = \(\frac{10}{0.5773}\)

x +8 = 17.3

x = 17.3 - 8

x = 9.32