JAMB Physics Past Questions & Answers - Page 82

His movements 1km due east and then 1 km due north make a Right-Angled Triangle.

Using Pythagoras' theorem;

The Resultant becomes the Hypotenuse [h]

Hyp\(^2\) = Adj\(^2\) + \Opp(^2\)

Hyp\(^2\) = 1\(^2\) + 1\(^2\)

Hyp\(^2\) = 2 → Hyp = √2

: Resultant = √2

DIRECTION TAN Ø = \(\frac{OPP}{ADJ}\) 

TAN Ø = \(\frac{1}{1}\)

Ø = TAN\(^{-1}\) [1]

Ø= 45°

Displacement is √2km N 45°E

An atom can be represented thus,

\(^{Z}_{A}X\) where Z = mass number

A = atomic number

A = number of proton = number of electrons in a free state = 28

Z = number of protons + number of neutrons = 28 + 30 = 58

\(^{58}_{28}X\)is the representation

Using boyle's law

P₁V₁ = P₂V₂

V₂ = \(\frac{P_1 V_1}{200}\) = \(\frac{400 \times 10}{200}\)

= 20cm³

Consider an inclined plane shown below, as the effort moves along OB, the load moves is lifted up through a vertical height AB

V.R = \(\frac{\text{distance moved by effort}}{\text{distance moved by load}}\) = \(\frac{OB}{AB}\)

But Sinθ = \(\frac{opp}{hyp}\) = \(\frac{AB}{OB}\)

therefore; = \(\frac{OB}{AB}\) = \(\frac{1}{\sin \theta}\)

Mechanical waves require material medium for their propagation only radio waves among the options docs require a material medium