N16,200
N14,200
N12,000
N8,000
Correct answer is A
Since it depreciates by 10% At the end of first year, its value = 90% of 20000
= \(\frac{90}{100}\) x 20000 =18000
At the end of second year, its value = 90% of 18000
= \(\frac{90}{100}\) x 18000 = ₦16,200
Answer is A
N676.50
N820
N1,640
N4,920
Correct answer is C
No explanation has been provided for this answer.
What is the place value of 9 in the number 3.0492?
\(\frac{9}{10000}\)
\(\frac{9}{1000}\)
\(\frac{9}{100}\)
\(\frac{9}{10}\)
Correct answer is B
No explanation has been provided for this answer.
Make T the subject of the relation.
T = \(\frac{R + P3}{15Q}\)
T = \(\frac{R - 15P^3}{Q}\)
T =R - \(\frac{15P^3}{Q}\)
T = \(\frac{15R + Q}{P^3}\)
Correct answer is C
P = (\(\frac{Q( R - T )}{ 15})^\frac{1}{3}\)
take cube of both sides
\(P^3 =\frac{Q( R - T)}{ 15}\)
cross multiply
\(15P^3 = Q( R - T)\)
\(\frac{15P^3}{Q}\) = R - T
T = R - \(\frac{15P^3}{Q}\)
25
1
\(\frac{1}{5}\)
\(\frac{1}{25}\)
Correct answer is A
\(\frac {25^{\frac{2}{3}} \div 25^{\frac{1}{6}}} {(\frac{1}{5})^{\frac{7}{6}} \div (\frac{1}{5})^{\frac{1}{6}}}\)
= \(\frac{25^{\frac{2}{3} - \frac{1}{6}}}{(\frac{1}{5})^{\frac{7}{6} - \frac{1}{6}}}\)
= \(\frac{25^{\frac{1}{2}}}{(\frac{1}{5})}\)
= \(5 \div \frac{1}{5}\)
= 25
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