JAMB Mathematics Past Questions & Answers - Page 70

346.

Use the quadratic equation curve to answer this questions
What is the minimum value of the graph?

A.

-5.3

B.

0.5

C.

3

D.

8

Correct answer is A

The minimum value is the lowest value of the curve on y axis which gives a value of -5.3

347.

Find the equation of the tangent at the point (2, 0) to the curve y = x\(^2\) - 2x

A.

y = 2x - 4

B.

y = 2x + 4

C.

y = 2x - 2

D.

y = 2x + 2

Correct answer is A

The gradient to the curve is found by differentiating the curve equation with respect to x

  So \(\frac{dy}{dx}\) 2x - 2

  The gradient of the curve is the same with that of the tangent.

  At point (2, 0) \(\frac{dy}{dx}\) = 2(2) - 2

  = 4 – 2 = 2

  The equation of the tangent is given by (y - y1) \(\frac{dy}{dx}\) (x – x1)

  At point (x1, y1) = (2, 0)

  y - 0 = 2(x - 2)

  y = 2x - 4

348.

Evaluate (2√3 - 4) (2√3 + 4) 

A.

-4

B.

-2

C.

2

D.

4

Correct answer is A

2√3 - 4) ( 2√3 + 4) = 12 + 8√3 - 8√3 – 16 = 12 – 16 = -4 The two expressions in the bracket are conjugate of each other

349.

Express 495g as a percentage of 16.5kg

A.

3%

B.

3 \(\frac{1}{3}\)%

C.

15%

D.

30%

Correct answer is A

The two numbers must be expressed in the same unit. To convert 495g to kg, it will be divided by 1000

  495g = \(\frac{495}{1000}\)

  = 0.495kg

  To express in percentage, 0.495 will be divided by 16.5 and then multiplied by 100

  % will be added to the answer \(\frac{0.4950}{16.5}\) x 100

  = 3%

350.

In the figure below, /MX/ = 8cm, /XN/ = 12cm, /NZ/ = 4cm and ∠ XMN = ∠ XZY. Calculate /YM/

A.

32cm

B.

24 cm

C.

16 cm

D.

12 cm

Correct answer is C

From the figure,

  ∠ XMN = ∠ XZY

  Angle X is common

  So, ∠ XNM = ∠ XYZ

  Then from the angle relationship

  \(\frac{XM}{XZ}\) = \(\frac{XN}{XY}\) = \(\frac{MN}{ZY}\)

  XM = 8, XZ = 12 + 4 = 16,

  XN = 12, XY = 8 + YM

  \(\frac{8}{16}\) = \(\frac{12}{(8 + YM) }\)

  Cross multiply

  8(8 + YM) = 192

  64 + 8YM = 192

  8YM = 128

  YM = \(\frac{128}{8}\)

  = 16cm