JAMB Mathematics Past Questions & Answers - Page 69

341.

What is the loci of a distance 4cm from a given point P?

A.

A straight line of length 4cm

B.

a circle of radius 4cm

C.

perpendicular to point P at 4cm

D.

a circle of diameter 4cm

Correct answer is B

Locus is the path traced at by a point which moves in accordance with a certain law. It is also the set of all possible position occupied by an object The path traced from all possible location of 4cm from a given point P form a circle of radius 4cm with centre P.

342.

The figure above is a Venn diagram showing the elements arranged within sets A,B,C,ε.
Use the figure to answer this question

What is n(A U B)1 ?

A.

2

B.

3

C.

4

D.

7

Correct answer is C

A = (p, q, r, t, u, v)

  B = (r, s, t, u)

  A U B = Elements in both A and B = (p, q, r, s, t, u, v)

  (A U B)1 = elements in the universal set E but not in (A U B)= (w, x, y, z)

  n(A U B) 1 = number of the elements in (A U B)1 = 4

343.

 

The table above shows the frequency of children age x years in a hospital
x 1 2 3 4 5 6 7 8
y 3 4 5 6 7 6 5 4

How many children are in the hospital

A.

36

B.

40

C.

44

D.

50

Correct answer is B

The total number of students is ∑ f = 3 + 4 + 5 + 6 + 7 + 6 + 5 + 4

  = 40

344.

Tanθ is positive and Sinθ is negative. In which quadrant does θ lies

A.

Second only

B.

Third only

C.

Fourth only

D.

First and third only

Correct answer is B

First quadrant: Sin, Cos and Tan are all positive Second quadrant: Sin is positive, Cos is negative and Tan is negative Third quadrant: Tan is positive, Sin is negative and Cos is negative Fourth quadrant: Cos is positive, Sin is negative and Tan is negative The correct option is the third quadrant only where Tanθ is positive and Sinθ is negative

345.

Evaluate log\(_2\) 8 – log\(_3\) \(\frac{1}{9}\)

A.

-1 1\(\frac{1}{2}\)

B.

-1

C.

1

D.

5

Correct answer is D

log\(_2\) 8 – log\(_3\) \(\frac{1}{9}\)

  = log \(_2\) 2\(^3\) – log\(_3\) 9\(^{-1}\)

  = log\(_2\) 2\(^3\) – log\(_3\) 3\(^{-2}\)

  Based on law of logarithm

  = 3 log\(_2\) 2 – (-2 log\(_3\) 3)

  But log\(_2\) 2 = 1,

  log\(_3\) 3 = 1

  So, = 3 + 2

  = 5