Convert 0.04945 to two significant figures
0.040
0.049
0.050
0.49
Correct answer is B
0.04945 to 2s.f is 0.049
4
5
6
7
Correct answer is B
The modal age is the age with the highest frequency, and that is age 5 years with f of 7
Find the average of the first four prime numbers greater than 10
20
19
17
15
Correct answer is D
Prime numbers are numbers that has only two factors (i.e 1 and itself). They are numbers that are only divisible by 1 and their selves. First four Prime numbers greater than 10 are 11, 13, 17 and 19
Average = sum of numbers / number
= \(frac{(11 + 13 + 17 + 19)}{4}\)
= \(\frac{60}{4}\)
= 15
Given that Sin (5\(_x\) − 28)\(^o\) = Cos(3\(_x\) − 50)\(^o\), o < x < 90\(^o\)
Find the value of x
14\(^o\)
21\(^o\)
32\(^o\)
39\(^o\)
Correct answer is B
Sin(5x - 28) = Cos(3x - 50)………..i
But Sinα = Cos(90 - α)
So Sin(5x - 28) = Cos(90 - [5x - 28])
Sin(5x - 28) = Cos(90 - 5x + 28)
Sin(5x - 28) = Cos(118 - 5x)………ii
Combining i and ii
Cos(3x - 50) = Cos(118 - 5x)
3x - 50 = 118 - 5x
Collecting the like terms
3x + 5x = 118 + 50
8x = 168
x = \(\frac{168}{8}\)
x = 21\(^o\)
Answer is B
Given that Sin (5\(_x\) − 28)\(^o\) = Cos(3\(_x\) − 50)\(^o\), o < x < 90\(^o\)
Find the value of x
14\(^o\)
21\(^o\)
32\(^o\)
39\(^o\)
Correct answer is B
Sin(5x - 28) = Cos(3x - 50)………..i
But Sinα = Cos(90 - α)
So Sin(5x - 28) = Cos(90 - [5x - 28])
Sin(5x - 28) = Cos(90 - 5x + 28)
Sin(5x - 28) = Cos(118 - 5x)………ii
Combining i and ii
Cos(3x - 50) = Cos(118 - 5x)
3x - 50 = 118 - 5x
Collecting the like terms
3x + 5x = 118 + 50
8x = 168
x = \(\frac{168}{8}\)
x = 21\(^o\)
Answer is B
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