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JAMB Mathematics Past Questions & Answers - Page 66

326.

Tanθ is positive and Sinθ is negative. In which quadrant does θ lies

A.

Second only

B.

Third only

C.

Fourth only

D.

First and third only

Correct answer is B

First quadrant: Sin, Cos and Tan are all positive Second quadrant: Sin is positive, Cos is negative and Tan is negative Third quadrant: Tan is positive, Sin is negative and Cos is negative Fourth quadrant: Cos is positive, Sin is negative and Tan is negative The correct option is the third quadrant only where Tanθ is positive and Sinθ is negative

327.

Evaluate log2 8 – log3 19

A.

-1 112

B.

-1

C.

1

D.

5

Correct answer is D

log2 8 – log3 19

  = log 2 23 – log3 91

  = log2 23 – log3 32

  Based on law of logarithm

  = 3 log2 2 – (-2 log3 3)

  But log2 2 = 1,

  log3 3 = 1

  So, = 3 + 2

  = 5

328.

Use the quadratic equation curve to answer this questions
What is the minimum value of the graph?

A.

-5.3

B.

0.5

C.

3

D.

8

Correct answer is A

The minimum value is the lowest value of the curve on y axis which gives a value of -5.3

329.

Find the equation of the tangent at the point (2, 0) to the curve y = x2 - 2x

A.

y = 2x - 4

B.

y = 2x + 4

C.

y = 2x - 2

D.

y = 2x + 2

Correct answer is A

The gradient to the curve is found by differentiating the curve equation with respect to x

  So dydx 2x - 2

  The gradient of the curve is the same with that of the tangent.

  At point (2, 0) dydx = 2(2) - 2

  = 4 – 2 = 2

  The equation of the tangent is given by (y - y1) dydx (x – x1)

  At point (x1, y1) = (2, 0)

  y - 0 = 2(x - 2)

  y = 2x - 4

330.

Evaluate (2√3 - 4) (2√3 + 4) 

A.

-4

B.

-2

C.

2

D.

4

Correct answer is A

2√3 - 4) ( 2√3 + 4) = 12 + 8√3 - 8√3 – 16 = 12 – 16 = -4 The two expressions in the bracket are conjugate of each other